Base | Representation |
---|---|
bin | 1011000110011000001110… |
… | …1011001111110100011110 |
3 | 1121012201012110112221211221 |
4 | 2301212003223033310132 |
5 | 3044423211034141342 |
6 | 41542312013403554 |
7 | 2366503505633551 |
oct | 261460353176436 |
9 | 47181173487757 |
10 | 12204211240222 |
11 | 398586009a121 |
12 | 14513117995ba |
13 | 6a6b10321981 |
14 | 3029890c0698 |
15 | 1626d5e44a67 |
hex | b1983acfd1e |
12204211240222 has 4 divisors (see below), whose sum is σ = 18306316860336. Its totient is φ = 6102105620110.
The previous prime is 12204211240219. The next prime is 12204211240271. The reversal of 12204211240222 is 22204211240221.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×122042112402222 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3051052810054 + ... + 3051052810057.
It is an arithmetic number, because the mean of its divisors is an integer number (4576579215084).
Almost surely, 212204211240222 is an apocalyptic number.
12204211240222 is a deficient number, since it is larger than the sum of its proper divisors (6102105620114).
12204211240222 is an equidigital number, since it uses as much as digits as its factorization.
12204211240222 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6102105620113.
The product of its (nonzero) digits is 2048, while the sum is 25.
Adding to 12204211240222 its reverse (22204211240221), we get a palindrome (34408422480443).
Subtracting 12204211240222 from its reverse (22204211240221), we obtain a palindrome (9999999999999).
The spelling of 12204211240222 in words is "twelve trillion, two hundred four billion, two hundred eleven million, two hundred forty thousand, two hundred twenty-two".
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