Base | Representation |
---|---|
bin | 10001110000100111010… |
… | …111010101010101111111 |
3 | 11022200010221111120102121 |
4 | 101300213113111111333 |
5 | 124443420332441343 |
6 | 2332354110503411 |
7 | 154113264346351 |
oct | 21604727252577 |
9 | 4280127446377 |
10 | 1220431140223 |
11 | 430644620149 |
12 | 17863bb04b67 |
13 | 8b1173b7ba9 |
14 | 430d7b9d0d1 |
15 | 21b2d71baed |
hex | 11c275d557f |
1220431140223 has 2 divisors, whose sum is σ = 1220431140224. Its totient is φ = 1220431140222.
The previous prime is 1220431140191. The next prime is 1220431140239. The reversal of 1220431140223 is 3220411340221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1220431140223 - 25 = 1220431140191 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1220431140283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610215570111 + 610215570112.
It is an arithmetic number, because the mean of its divisors is an integer number (610215570112).
Almost surely, 21220431140223 is an apocalyptic number.
1220431140223 is a deficient number, since it is larger than the sum of its proper divisors (1).
1220431140223 is an equidigital number, since it uses as much as digits as its factorization.
1220431140223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 1220431140223 its reverse (3220411340221), we get a palindrome (4440842480444).
The spelling of 1220431140223 in words is "one trillion, two hundred twenty billion, four hundred thirty-one million, one hundred forty thousand, two hundred twenty-three".
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