Base | Representation |
---|---|
bin | 10001110000100111011… |
… | …100100010100100010011 |
3 | 11022200011001001220200212 |
4 | 101300213130202210103 |
5 | 124443421210130412 |
6 | 2332354200034335 |
7 | 154113312062534 |
oct | 21604734424423 |
9 | 4280131056625 |
10 | 1220432505107 |
11 | 430645372652 |
12 | 1786404629ab |
13 | 8b11777520a |
14 | 430d803668b |
15 | 21b2d8db222 |
hex | 11c27722913 |
1220432505107 has 2 divisors, whose sum is σ = 1220432505108. Its totient is φ = 1220432505106.
The previous prime is 1220432505037. The next prime is 1220432505109. The reversal of 1220432505107 is 7015052340221.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1220432505107 is a prime.
It is a super-3 number, since 3×12204325051073 (a number of 37 digits) contains 333 as substring.
Together with 1220432505109, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1220432505109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610216252553 + 610216252554.
It is an arithmetic number, because the mean of its divisors is an integer number (610216252554).
Almost surely, 21220432505107 is an apocalyptic number.
1220432505107 is a deficient number, since it is larger than the sum of its proper divisors (1).
1220432505107 is an equidigital number, since it uses as much as digits as its factorization.
1220432505107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16800, while the sum is 32.
Adding to 1220432505107 its reverse (7015052340221), we get a palindrome (8235484845328).
The spelling of 1220432505107 in words is "one trillion, two hundred twenty billion, four hundred thirty-two million, five hundred five thousand, one hundred seven".
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