Base | Representation |
---|---|
bin | 10001110000100111011… |
… | …110110110110101110011 |
3 | 11022200011002012202210111 |
4 | 101300213132312311303 |
5 | 124443421334044220 |
6 | 2332354221042151 |
7 | 154113320202265 |
oct | 21604736666563 |
9 | 4280132182714 |
10 | 1220433112435 |
11 | 430645747979 |
12 | 1786406b6357 |
13 | 8b117928794 |
14 | 430d8153b35 |
15 | 21b2d9ab15a |
hex | 11c277b6d73 |
1220433112435 has 8 divisors (see below), whose sum is σ = 1464594205536. Its totient is φ = 976296842880.
The previous prime is 1220433112429. The next prime is 1220433112517. The reversal of 1220433112435 is 5342113340221.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1220433112435 - 213 = 1220433104243 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1220433112397 and 1220433112406.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6097551 + ... + 6294520.
It is an arithmetic number, because the mean of its divisors is an integer number (183074275692).
Almost surely, 21220433112435 is an apocalyptic number.
1220433112435 is a deficient number, since it is larger than the sum of its proper divisors (244161093101).
1220433112435 is a wasteful number, since it uses less digits than its factorization.
1220433112435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12411773.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 1220433112435 its reverse (5342113340221), we get a palindrome (6562546452656).
The spelling of 1220433112435 in words is "one trillion, two hundred twenty billion, four hundred thirty-three million, one hundred twelve thousand, four hundred thirty-five".
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