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12205319999993 is a prime number
BaseRepresentation
bin1011000110011100010111…
…0000110101000111111001
31121012211001201212210022122
42301213011300311013321
53044432443404444433
641543014022131025
72366543131142411
oct261470560650771
947184051783278
1012205319999993
113986279a4780a
121451580b80a75
136a6c58c4b843
14302a5245d641
1516274d45b198
hexb19c5c351f9

12205319999993 has 2 divisors, whose sum is σ = 12205319999994. Its totient is φ = 12205319999992.

The previous prime is 12205319999911. The next prime is 12205320000043. The reversal of 12205319999993 is 39999991350221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11160891187264 + 1044428812729 = 3340792^2 + 1021973^2 .

It is a cyclic number.

It is not a de Polignac number, because 12205319999993 - 28 = 12205319999737 is a prime.

It is not a weakly prime, because it can be changed into another prime (12205319999393) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6102659999996 + 6102659999997.

It is an arithmetic number, because the mean of its divisors is an integer number (6102659999997).

Almost surely, 212205319999993 is an apocalyptic number.

It is an amenable number.

12205319999993 is a deficient number, since it is larger than the sum of its proper divisors (1).

12205319999993 is an equidigital number, since it uses as much as digits as its factorization.

12205319999993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 95659380, while the sum is 71.

The spelling of 12205319999993 in words is "twelve trillion, two hundred five billion, three hundred nineteen million, nine hundred ninety-nine thousand, nine hundred ninety-three".