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1220544052433 is a prime number
BaseRepresentation
bin10001110000101110000…
…110000011110011010001
311022200102210222002212022
4101300232012003303101
5124444133234134213
62332413222541225
7154116135160436
oct21605606036321
94280383862768
101220544052433
114306a2330822
12178671897815
138b1348cc954
1443108b91b8d
1521b385c2308
hex11c2e183cd1

1220544052433 has 2 divisors, whose sum is σ = 1220544052434. Its totient is φ = 1220544052432.

The previous prime is 1220544052421. The next prime is 1220544052447. The reversal of 1220544052433 is 3342504450221.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 676708600129 + 543835452304 = 822623^2 + 737452^2 .

It is a cyclic number.

It is not a de Polignac number, because 1220544052433 - 234 = 1203364183249 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1220544052393 and 1220544052402.

It is not a weakly prime, because it can be changed into another prime (1220544052633) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610272026216 + 610272026217.

It is an arithmetic number, because the mean of its divisors is an integer number (610272026217).

Almost surely, 21220544052433 is an apocalyptic number.

It is an amenable number.

1220544052433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1220544052433 is an equidigital number, since it uses as much as digits as its factorization.

1220544052433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 115200, while the sum is 35.

The spelling of 1220544052433 in words is "one trillion, two hundred twenty billion, five hundred forty-four million, fifty-two thousand, four hundred thirty-three".