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12205545096149 is a prime number
BaseRepresentation
bin1011000110011101001100…
…1011100000001111010101
31121012211122102102212012022
42301213103023200033111
53044433424021034044
641543052222502525
72366551533342416
oct261472313401725
947184572385168
1012205545096149
113986385010899
121451624434a45
136a6c93781a32
14302a742d580d
151627630c13ee
hexb19d32e03d5

12205545096149 has 2 divisors, whose sum is σ = 12205545096150. Its totient is φ = 12205545096148.

The previous prime is 12205545096139. The next prime is 12205545096161. The reversal of 12205545096149 is 94169054550221.

12205545096149 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10697543904100 + 1508001192049 = 3270710^2 + 1228007^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12205545096149 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 12205545096149.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12205545096139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6102772548074 + 6102772548075.

It is an arithmetic number, because the mean of its divisors is an integer number (6102772548075).

Almost surely, 212205545096149 is an apocalyptic number.

It is an amenable number.

12205545096149 is a deficient number, since it is larger than the sum of its proper divisors (1).

12205545096149 is an equidigital number, since it uses as much as digits as its factorization.

12205545096149 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3888000, while the sum is 53.

The spelling of 12205545096149 in words is "twelve trillion, two hundred five billion, five hundred forty-five million, ninety-six thousand, one hundred forty-nine".