Base | Representation |
---|---|
bin | 10110101111011011… |
… | …01001110111101011 |
3 | 1011111212101122221202 |
4 | 23113231221313223 |
5 | 200001001112021 |
6 | 5335253154415 |
7 | 611356551611 |
oct | 132755516753 |
9 | 34455348852 |
10 | 12209004011 |
11 | 51a5734466 |
12 | 244892ba0b |
13 | 11c7552239 |
14 | 83b6a56b1 |
15 | 4b6ca7a0b |
hex | 2d7b69deb |
12209004011 has 2 divisors, whose sum is σ = 12209004012. Its totient is φ = 12209004010.
The previous prime is 12209003993. The next prime is 12209004023. The reversal of 12209004011 is 11040090221.
It is a strong prime.
It is an emirp because it is prime and its reverse (11040090221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12209004011 - 222 = 12204809707 is a prime.
It is a super-2 number, since 2×122090040112 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12209004091) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6104502005 + 6104502006.
It is an arithmetic number, because the mean of its divisors is an integer number (6104502006).
Almost surely, 212209004011 is an apocalyptic number.
12209004011 is a deficient number, since it is larger than the sum of its proper divisors (1).
12209004011 is an equidigital number, since it uses as much as digits as its factorization.
12209004011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 12209004011 its reverse (11040090221), we get a palindrome (23249094232).
The spelling of 12209004011 in words is "twelve billion, two hundred nine million, four thousand, eleven".
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