Base | Representation |
---|---|
bin | 10110101111100010… |
… | …11101000001010001 |
3 | 1011111221021021010111 |
4 | 23113301131001101 |
5 | 200001224444303 |
6 | 5335330401321 |
7 | 611401200334 |
oct | 132761350121 |
9 | 34457237114 |
10 | 12209999953 |
11 | 51a6254758 |
12 | 2449130241 |
13 | 11c7810658 |
14 | 83b88461b |
15 | 4b6e02b6d |
hex | 2d7c5d051 |
12209999953 has 2 divisors, whose sum is σ = 12209999954. Its totient is φ = 12209999952.
The previous prime is 12209999927. The next prime is 12209999959. The reversal of 12209999953 is 35999990221.
12209999953 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8772757569 + 3437242384 = 93663^2 + 58628^2 .
It is a cyclic number.
It is not a de Polignac number, because 12209999953 - 221 = 12207902801 is a prime.
It is not a weakly prime, because it can be changed into another prime (12209999959) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6104999976 + 6104999977.
It is an arithmetic number, because the mean of its divisors is an integer number (6104999977).
Almost surely, 212209999953 is an apocalyptic number.
It is an amenable number.
12209999953 is a deficient number, since it is larger than the sum of its proper divisors (1).
12209999953 is an equidigital number, since it uses as much as digits as its factorization.
12209999953 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3542940, while the sum is 58.
The spelling of 12209999953 in words is "twelve billion, two hundred nine million, nine hundred ninety-nine thousand, nine hundred fifty-three".
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