Base | Representation |
---|---|
bin | 1011000110101101110101… |
… | …0100111010001001111011 |
3 | 1121020021011121111202210122 |
4 | 2301223131110322021323 |
5 | 3100022100114113201 |
6 | 41545111251403455 |
7 | 2400100303063463 |
oct | 261533524721173 |
9 | 47207147452718 |
10 | 12210010301051 |
11 | 3988266556382 |
12 | 145246b8b358b |
13 | 6a7525894b04 |
14 | 302d79344ba3 |
15 | 1629250d9e1b |
hex | b1add53a27b |
12210010301051 has 2 divisors, whose sum is σ = 12210010301052. Its totient is φ = 12210010301050.
The previous prime is 12210010301029. The next prime is 12210010301057. The reversal of 12210010301051 is 15010301001221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12210010301051 - 222 = 12210006106747 is a prime.
It is not a weakly prime, because it can be changed into another prime (12210010301057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6105005150525 + 6105005150526.
It is an arithmetic number, because the mean of its divisors is an integer number (6105005150526).
Almost surely, 212210010301051 is an apocalyptic number.
12210010301051 is a deficient number, since it is larger than the sum of its proper divisors (1).
12210010301051 is an equidigital number, since it uses as much as digits as its factorization.
12210010301051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 60, while the sum is 17.
Adding to 12210010301051 its reverse (15010301001221), we get a palindrome (27220311302272).
The spelling of 12210010301051 in words is "twelve trillion, two hundred ten billion, ten million, three hundred one thousand, fifty-one".
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