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122100130003 = 949112864833
BaseRepresentation
bin111000110110110111…
…1000010000011010011
3102200011100221021021011
41301231233002003103
54000030113130003
6132031513311351
711551516660255
oct1615557020323
9380140837234
10122100130003
1147867381955
121b7b7105557
13b68b31c447
145ca4227cd5
15329954646d
hex1c6dbc20d3

122100130003 has 4 divisors (see below), whose sum is σ = 122113004328. Its totient is φ = 122087255680.

The previous prime is 122100129971. The next prime is 122100130007. The reversal of 122100130003 is 300031001221.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 122100130003 - 25 = 122100129971 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (122100130007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6422926 + ... + 6441907.

It is an arithmetic number, because the mean of its divisors is an integer number (30528251082).

Almost surely, 2122100130003 is an apocalyptic number.

122100130003 is a deficient number, since it is larger than the sum of its proper divisors (12874325).

122100130003 is an equidigital number, since it uses as much as digits as its factorization.

122100130003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12874324.

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 122100130003 its reverse (300031001221), we get a palindrome (422131131224).

The spelling of 122100130003 in words is "one hundred twenty-two billion, one hundred million, one hundred thirty thousand, three".

Divisors: 1 9491 12864833 122100130003