Base | Representation |
---|---|
bin | 10001110001001001111… |
… | …100001010011010011111 |
3 | 11022201122101000200110111 |
4 | 101301021330022122133 |
5 | 130001112333021002 |
6 | 2332531431550451 |
7 | 154133540061406 |
oct | 21611174123237 |
9 | 4281571020414 |
10 | 1221011220127 |
11 | 430912002826 |
12 | 17878222b427 |
13 | 8b1aa62a83a |
14 | 43150c3c63d |
15 | 21b646023d7 |
hex | 11c49f0a69f |
1221011220127 has 2 divisors, whose sum is σ = 1221011220128. Its totient is φ = 1221011220126.
The previous prime is 1221011220061. The next prime is 1221011220167. The reversal of 1221011220127 is 7210221101221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1221011220127 - 211 = 1221011218079 is a prime.
It is a super-2 number, since 2×12210112201272 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1221011220098 and 1221011220107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1221011220167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610505610063 + 610505610064.
It is an arithmetic number, because the mean of its divisors is an integer number (610505610064).
Almost surely, 21221011220127 is an apocalyptic number.
1221011220127 is a deficient number, since it is larger than the sum of its proper divisors (1).
1221011220127 is an equidigital number, since it uses as much as digits as its factorization.
1221011220127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 224, while the sum is 22.
Adding to 1221011220127 its reverse (7210221101221), we get a palindrome (8431232321348).
The spelling of 1221011220127 in words is "one trillion, two hundred twenty-one billion, eleven million, two hundred twenty thousand, one hundred twenty-seven".
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