Base | Representation |
---|---|
bin | 10001110001001111010… |
… | …010101110011101111011 |
3 | 11022201212122000001011122 |
4 | 101301033102232131323 |
5 | 130001303330133201 |
6 | 2332544400415455 |
7 | 154136010264602 |
oct | 21611722563573 |
9 | 4281778001148 |
10 | 1221101021051 |
11 | 43095876856a |
12 | 1787a831758b |
13 | 8b1c310cc92 |
14 | 4315cb36a39 |
15 | 21b6c43ee1b |
hex | 11c4f4ae77b |
1221101021051 has 2 divisors, whose sum is σ = 1221101021052. Its totient is φ = 1221101021050.
The previous prime is 1221101021047. The next prime is 1221101021123. The reversal of 1221101021051 is 1501201011221.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1221101021051 - 22 = 1221101021047 is a prime.
It is a super-2 number, since 2×12211010210512 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1221101029051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610550510525 + 610550510526.
It is an arithmetic number, because the mean of its divisors is an integer number (610550510526).
Almost surely, 21221101021051 is an apocalyptic number.
1221101021051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1221101021051 is an equidigital number, since it uses as much as digits as its factorization.
1221101021051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40, while the sum is 17.
Adding to 1221101021051 its reverse (1501201011221), we get a palindrome (2722302032272).
The spelling of 1221101021051 in words is "one trillion, two hundred twenty-one billion, one hundred one million, twenty-one thousand, fifty-one".
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