Base | Representation |
---|---|
bin | 10001110001001111011… |
… | …011001000100110001111 |
3 | 11022201212210011000201221 |
4 | 101301033123020212033 |
5 | 130001304411201411 |
6 | 2332544515544211 |
7 | 154136035105021 |
oct | 21611733104617 |
9 | 4281783130657 |
10 | 1221103225231 |
11 | 430959a335aa |
12 | 1787a8bbb067 |
13 | 8b1c3702326 |
14 | 4315d14c011 |
15 | 21b6c728071 |
hex | 11c4f6c898f |
1221103225231 has 2 divisors, whose sum is σ = 1221103225232. Its totient is φ = 1221103225230.
The previous prime is 1221103225201. The next prime is 1221103225249. The reversal of 1221103225231 is 1325223011221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1221103225231 - 211 = 1221103223183 is a prime.
It is a super-2 number, since 2×12211032252312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1221103225196 and 1221103225205.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1221103225201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610551612615 + 610551612616.
It is an arithmetic number, because the mean of its divisors is an integer number (610551612616).
Almost surely, 21221103225231 is an apocalyptic number.
1221103225231 is a deficient number, since it is larger than the sum of its proper divisors (1).
1221103225231 is an equidigital number, since it uses as much as digits as its factorization.
1221103225231 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 1221103225231 its reverse (1325223011221), we get a palindrome (2546326236452).
The spelling of 1221103225231 in words is "one trillion, two hundred twenty-one billion, one hundred three million, two hundred twenty-five thousand, two hundred thirty-one".
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