Base | Representation |
---|---|
bin | 10110101111101011… |
… | …01001100111110011 |
3 | 1011112000100011022102 |
4 | 23113311221213303 |
5 | 200002020201042 |
6 | 5335410131015 |
7 | 611413432031 |
oct | 132765514763 |
9 | 34460304272 |
10 | 12211100147 |
11 | 51a6936304 |
12 | 2449580a6b |
13 | 11c7b0735c |
14 | 83ba8d551 |
15 | 4b706db32 |
hex | 2d7d699f3 |
12211100147 has 2 divisors, whose sum is σ = 12211100148. Its totient is φ = 12211100146.
The previous prime is 12211100009. The next prime is 12211100149. The reversal of 12211100147 is 74100111221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12211100147 - 28 = 12211099891 is a prime.
It is a super-2 number, since 2×122111001472 (a number of 21 digits) contains 22 as substring.
Together with 12211100149, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (12211100149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6105550073 + 6105550074.
It is an arithmetic number, because the mean of its divisors is an integer number (6105550074).
Almost surely, 212211100147 is an apocalyptic number.
12211100147 is a deficient number, since it is larger than the sum of its proper divisors (1).
12211100147 is an equidigital number, since it uses as much as digits as its factorization.
12211100147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112, while the sum is 20.
Adding to 12211100147 its reverse (74100111221), we get a palindrome (86311211368).
The spelling of 12211100147 in words is "twelve billion, two hundred eleven million, one hundred thousand, one hundred forty-seven".
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