Base | Representation |
---|---|
bin | 11011110000111100101110… |
… | …111001011100001010100011 |
3 | 121000100200211200110211201212 |
4 | 123300330232321130022203 |
5 | 112001131313003031313 |
6 | 1111413004144020335 |
7 | 34502141315142443 |
oct | 3360745671341243 |
9 | 530320750424655 |
10 | 122111002002083 |
11 | 359a9a922260a6 |
12 | 11841b1b6016ab |
13 | 531a030949483 |
14 | 22222bdc12123 |
15 | e1b5c26a53a8 |
hex | 6f0f2ee5c2a3 |
122111002002083 has 2 divisors, whose sum is σ = 122111002002084. Its totient is φ = 122111002002082.
The previous prime is 122111002002049. The next prime is 122111002002113. The reversal of 122111002002083 is 380200200111221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 122111002002083 - 214 = 122111001985699 is a prime.
It is a super-2 number, since 2×1221110020020832 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (122111002002023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61055501001041 + 61055501001042.
It is an arithmetic number, because the mean of its divisors is an integer number (61055501001042).
Almost surely, 2122111002002083 is an apocalyptic number.
122111002002083 is a deficient number, since it is larger than the sum of its proper divisors (1).
122111002002083 is an equidigital number, since it uses as much as digits as its factorization.
122111002002083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 23.
The spelling of 122111002002083 in words is "one hundred twenty-two trillion, one hundred eleven billion, two million, two thousand, eighty-three".
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