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12211120109983 is a prime number
BaseRepresentation
bin1011000110110001111101…
…1110011111100110011111
31121020101000221210220110011
42301230133132133212133
53100031333222004413
641545413334424051
72400136640232154
oct261543736374637
947211027726404
1012211120109983
113988785a60243
12145271b502027
136a767179b3a2
143030428b822b
1516298c75c33d
hexb1b1f79f99f

12211120109983 has 2 divisors, whose sum is σ = 12211120109984. Its totient is φ = 12211120109982.

The previous prime is 12211120109941. The next prime is 12211120110061. The reversal of 12211120109983 is 38990102111221.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12211120109983 is a prime.

It is a super-2 number, since 2×122111201099832 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12211120109933) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6105560054991 + 6105560054992.

It is an arithmetic number, because the mean of its divisors is an integer number (6105560054992).

Almost surely, 212211120109983 is an apocalyptic number.

12211120109983 is a deficient number, since it is larger than the sum of its proper divisors (1).

12211120109983 is an equidigital number, since it uses as much as digits as its factorization.

12211120109983 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15552, while the sum is 40.

The spelling of 12211120109983 in words is "twelve trillion, two hundred eleven billion, one hundred twenty million, one hundred nine thousand, nine hundred eighty-three".