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12211210020043 is a prime number
BaseRepresentation
bin1011000110110010010011…
…0101011110010011001011
31121020101021012222210212101
42301230210311132103023
53100032024231120133
641545430305454231
72400142111401466
oct261544465362313
947211235883771
1012211210020043
11398882178aa81
121452745641377
136a76872bb3c8
143030508002dd
151629955bc37d
hexb1b24d5e4cb

12211210020043 has 2 divisors, whose sum is σ = 12211210020044. Its totient is φ = 12211210020042.

The previous prime is 12211210019951. The next prime is 12211210020049. The reversal of 12211210020043 is 34002001211221.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12211210020043 - 217 = 12211209888971 is a prime.

It is a super-2 number, since 2×122112100200432 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 12211210020043.

It is not a weakly prime, because it can be changed into another prime (12211210020049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6105605010021 + 6105605010022.

It is an arithmetic number, because the mean of its divisors is an integer number (6105605010022).

Almost surely, 212211210020043 is an apocalyptic number.

12211210020043 is a deficient number, since it is larger than the sum of its proper divisors (1).

12211210020043 is an equidigital number, since it uses as much as digits as its factorization.

12211210020043 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 12211210020043 its reverse (34002001211221), we get a palindrome (46213211231264).

The spelling of 12211210020043 in words is "twelve trillion, two hundred eleven billion, two hundred ten million, twenty thousand, forty-three".