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12211212222113 is a prime number
BaseRepresentation
bin1011000110110010010011…
…1101110111111010100001
31121020101021101010200112112
42301230210331313322201
53100032030312101423
641545430425005105
72400142136202512
oct261544475677241
947211241120475
1012211212222113
113988822a54473
121452746323795
136a76878ac7c8
14303050c14a09
151629958a4a78
hexb1b24f77ea1

12211212222113 has 2 divisors, whose sum is σ = 12211212222114. Its totient is φ = 12211212222112.

The previous prime is 12211212221933. The next prime is 12211212222119. The reversal of 12211212222113 is 31122221211221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7753067131489 + 4458145090624 = 2784433^2 + 2111432^2 .

It is a cyclic number.

It is not a de Polignac number, because 12211212222113 - 232 = 12206917254817 is a prime.

It is a super-2 number, since 2×122112122221132 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12211212222119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6105606111056 + 6105606111057.

It is an arithmetic number, because the mean of its divisors is an integer number (6105606111057).

Almost surely, 212211212222113 is an apocalyptic number.

It is an amenable number.

12211212222113 is a deficient number, since it is larger than the sum of its proper divisors (1).

12211212222113 is an equidigital number, since it uses as much as digits as its factorization.

12211212222113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 384, while the sum is 23.

Adding to 12211212222113 its reverse (31122221211221), we get a palindrome (43333433433334).

The spelling of 12211212222113 in words is "twelve trillion, two hundred eleven billion, two hundred twelve million, two hundred twenty-two thousand, one hundred thirteen".