Base | Representation |
---|---|
bin | 11011110000111110101011… |
… | …111100111000000001011111 |
3 | 121000100220020220022221202111 |
4 | 123300332223330320001133 |
5 | 112001200112103221443 |
6 | 1111413552252334451 |
7 | 34502244312245626 |
oct | 3360765374700137 |
9 | 530326226287674 |
10 | 122113100054623 |
11 | 359aa969554017 |
12 | 11842406174427 |
13 | 531a2a6504a92 |
14 | 222243c7126bd |
15 | e1b69698569d |
hex | 6f0fabf3805f |
122113100054623 has 2 divisors, whose sum is σ = 122113100054624. Its totient is φ = 122113100054622.
The previous prime is 122113100054609. The next prime is 122113100054651. The reversal of 122113100054623 is 326450001311221.
It is a weak prime.
It is an emirp because it is prime and its reverse (326450001311221) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-122113100054623 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (122113100052623) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61056550027311 + 61056550027312.
It is an arithmetic number, because the mean of its divisors is an integer number (61056550027312).
Almost surely, 2122113100054623 is an apocalyptic number.
122113100054623 is a deficient number, since it is larger than the sum of its proper divisors (1).
122113100054623 is an equidigital number, since it uses as much as digits as its factorization.
122113100054623 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 31.
Adding to 122113100054623 its reverse (326450001311221), we get a palindrome (448563101365844).
The spelling of 122113100054623 in words is "one hundred twenty-two trillion, one hundred thirteen billion, one hundred million, fifty-four thousand, six hundred twenty-three".
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