Base | Representation |
---|---|
bin | 10001110001010001001… |
… | …000111001101100000111 |
3 | 11022201221210021221022101 |
4 | 101301101020321230013 |
5 | 130001334243000012 |
6 | 2332551424412531 |
7 | 154136534511343 |
oct | 21612110715407 |
9 | 4281853257271 |
10 | 1221132000007 |
11 | 4309741a7507 |
12 | 1787b6777147 |
13 | 8b1c966871a |
14 | 43162cbc623 |
15 | 21b7000dd57 |
hex | 11c51239b07 |
1221132000007 has 2 divisors, whose sum is σ = 1221132000008. Its totient is φ = 1221132000006.
The previous prime is 1221131999987. The next prime is 1221132000059. The reversal of 1221132000007 is 7000002311221.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1221132000007 is a prime.
It is a super-2 number, since 2×12211320000072 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1221132000107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610566000003 + 610566000004.
It is an arithmetic number, because the mean of its divisors is an integer number (610566000004).
Almost surely, 21221132000007 is an apocalyptic number.
1221132000007 is a deficient number, since it is larger than the sum of its proper divisors (1).
1221132000007 is an equidigital number, since it uses as much as digits as its factorization.
1221132000007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 168, while the sum is 19.
Adding to 1221132000007 its reverse (7000002311221), we get a palindrome (8221134311228).
The spelling of 1221132000007 in words is "one trillion, two hundred twenty-one billion, one hundred thirty-two million, seven", and thus it is an aban number.
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