Base | Representation |
---|---|
bin | 10110101111101101… |
… | …10101100101100111 |
3 | 1011112000220222010201 |
4 | 23113312311211213 |
5 | 200002110130203 |
6 | 5335420531331 |
7 | 611416166140 |
oct | 132766654547 |
9 | 34460828121 |
10 | 12211411303 |
11 | 51a7029063 |
12 | 24496b0b47 |
13 | 11c7bb5b80 |
14 | 83bb30ac7 |
15 | 4b70d0e1d |
hex | 2d7db5967 |
12211411303 has 16 divisors (see below), whose sum is σ = 15042078016. Its totient is φ = 9653644800.
The previous prime is 12211411297. The next prime is 12211411313. The reversal of 12211411303 is 30311411221.
It is a cyclic number.
It is not a de Polignac number, because 12211411303 - 213 = 12211403111 is a prime.
It is a super-2 number, since 2×122114113032 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12211411313) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 53425 + ... + 165157.
It is an arithmetic number, because the mean of its divisors is an integer number (940129876).
Almost surely, 212211411303 is an apocalyptic number.
12211411303 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
12211411303 is a deficient number, since it is larger than the sum of its proper divisors (2830666713).
12211411303 is a wasteful number, since it uses less digits than its factorization.
12211411303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 112954.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 12211411303 its reverse (30311411221), we get a palindrome (42522822524).
The spelling of 12211411303 in words is "twelve billion, two hundred eleven million, four hundred eleven thousand, three hundred three".
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