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12211411303 = 7131201111733
BaseRepresentation
bin10110101111101101…
…10101100101100111
31011112000220222010201
423113312311211213
5200002110130203
65335420531331
7611416166140
oct132766654547
934460828121
1012211411303
1151a7029063
1224496b0b47
1311c7bb5b80
1483bb30ac7
154b70d0e1d
hex2d7db5967

12211411303 has 16 divisors (see below), whose sum is σ = 15042078016. Its totient is φ = 9653644800.

The previous prime is 12211411297. The next prime is 12211411313. The reversal of 12211411303 is 30311411221.

It is a cyclic number.

It is not a de Polignac number, because 12211411303 - 213 = 12211403111 is a prime.

It is a super-2 number, since 2×122114113032 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12211411313) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 53425 + ... + 165157.

It is an arithmetic number, because the mean of its divisors is an integer number (940129876).

Almost surely, 212211411303 is an apocalyptic number.

12211411303 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

12211411303 is a deficient number, since it is larger than the sum of its proper divisors (2830666713).

12211411303 is a wasteful number, since it uses less digits than its factorization.

12211411303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 112954.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 12211411303 its reverse (30311411221), we get a palindrome (42522822524).

The spelling of 12211411303 in words is "twelve billion, two hundred eleven million, four hundred eleven thousand, three hundred three".

Divisors: 1 7 13 91 1201 8407 15613 109291 111733 782131 1452529 10167703 134191333 939339331 1744487329 12211411303