Base | Representation |
---|---|
bin | 10001110001010010011… |
… | …001100101110000101111 |
3 | 11022202000021002120110021 |
4 | 101301102121211300233 |
5 | 130001410201331142 |
6 | 2332553502023011 |
7 | 154140212346163 |
oct | 21612231456057 |
9 | 4282007076407 |
10 | 1221153152047 |
11 | 430985134334 |
12 | 178801877a67 |
13 | 8b200b6331a |
14 | 43165a26ca3 |
15 | 21b71cdb267 |
hex | 11c52665c2f |
1221153152047 has 2 divisors, whose sum is σ = 1221153152048. Its totient is φ = 1221153152046.
The previous prime is 1221153152003. The next prime is 1221153152071. The reversal of 1221153152047 is 7402513511221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1221153152047 - 223 = 1221144763439 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1221153152147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610576576023 + 610576576024.
It is an arithmetic number, because the mean of its divisors is an integer number (610576576024).
Almost surely, 21221153152047 is an apocalyptic number.
1221153152047 is a deficient number, since it is larger than the sum of its proper divisors (1).
1221153152047 is an equidigital number, since it uses as much as digits as its factorization.
1221153152047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16800, while the sum is 34.
Adding to 1221153152047 its reverse (7402513511221), we get a palindrome (8623666663268).
The spelling of 1221153152047 in words is "one trillion, two hundred twenty-one billion, one hundred fifty-three million, one hundred fifty-two thousand, forty-seven".
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