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12211662472151 is a prime number
BaseRepresentation
bin1011000110110011111111…
…0011011100001111010111
31121020102102202100202110212
42301230333303130033113
53100033441043102101
641545543231240035
72400156244233032
oct261547763341727
947212382322425
1012211662472151
113988a34120a3a
12145285107901b
136a7729c6624c
1430309493a019
151629c01921bb
hexb1b3fcdc3d7

12211662472151 has 2 divisors, whose sum is σ = 12211662472152. Its totient is φ = 12211662472150.

The previous prime is 12211662472147. The next prime is 12211662472157. The reversal of 12211662472151 is 15127426611221.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 12211662472151 - 22 = 12211662472147 is a prime.

It is a super-3 number, since 3×122116624721513 (a number of 40 digits) contains 333 as substring.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 12211662472099 and 12211662472108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12211662472157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6105831236075 + 6105831236076.

It is an arithmetic number, because the mean of its divisors is an integer number (6105831236076).

Almost surely, 212211662472151 is an apocalyptic number.

12211662472151 is a deficient number, since it is larger than the sum of its proper divisors (1).

12211662472151 is an equidigital number, since it uses as much as digits as its factorization.

12211662472151 is an evil number, because the sum of its binary digits is even.

The product of its digits is 80640, while the sum is 41.

The spelling of 12211662472151 in words is "twelve trillion, two hundred eleven billion, six hundred sixty-two million, four hundred seventy-two thousand, one hundred fifty-one".