Base | Representation |
---|---|
bin | 1011000110110101010100… |
… | …0111010011100101100010 |
3 | 1121020110100200010010000121 |
4 | 2301231111013103211202 |
5 | 3100040204110013442 |
6 | 41550042522310454 |
7 | 2400201145205404 |
oct | 261552507234542 |
9 | 47213320103017 |
10 | 12212020001122 |
11 | 39890a7a18827 |
12 | 145293095842a |
13 | 6a7786057356 |
14 | 3030ca206b74 |
15 | 1629e1766967 |
hex | b1b551d3962 |
12212020001122 has 4 divisors (see below), whose sum is σ = 18318030001686. Its totient is φ = 6106010000560.
The previous prime is 12212020001081. The next prime is 12212020001173. The reversal of 12212020001122 is 22110002021221.
It is a happy number.
12212020001122 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 11802254864481 + 409765136641 = 3435441^2 + 640129^2 .
It is a junction number, because it is equal to n+sod(n) for n = 12212020001096 and 12212020001105.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3053005000279 + ... + 3053005000282.
Almost surely, 212212020001122 is an apocalyptic number.
12212020001122 is a deficient number, since it is larger than the sum of its proper divisors (6106010000564).
12212020001122 is an equidigital number, since it uses as much as digits as its factorization.
12212020001122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6106010000563.
The product of its (nonzero) digits is 64, while the sum is 16.
Adding to 12212020001122 its reverse (22110002021221), we get a palindrome (34322022022343).
The spelling of 12212020001122 in words is "twelve trillion, two hundred twelve billion, twenty million, one thousand, one hundred twenty-two".
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