Search a number
-
+
1221211122233 is a prime number
BaseRepresentation
bin10001110001010101110…
…110101110101000111001
311022202011022011202121012
4101301111312232220321
5130002020021402413
62333003332323305
7154141515160364
oct21612566565071
94282138152535
101221211122233
11430a04929183
12178819173535
138b20cb7c3cb
144316d5d70db
1521b76e3c7a8
hex11c55daea39

1221211122233 has 2 divisors, whose sum is σ = 1221211122234. Its totient is φ = 1221211122232.

The previous prime is 1221211122163. The next prime is 1221211122269. The reversal of 1221211122233 is 3322211121221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1055279543824 + 165931578409 = 1027268^2 + 407347^2 .

It is an emirp because it is prime and its reverse (3322211121221) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1221211122233 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1221211122199 and 1221211122208.

It is not a weakly prime, because it can be changed into another prime (1221211122283) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610605561116 + 610605561117.

It is an arithmetic number, because the mean of its divisors is an integer number (610605561117).

Almost surely, 21221211122233 is an apocalyptic number.

It is an amenable number.

1221211122233 is a deficient number, since it is larger than the sum of its proper divisors (1).

1221211122233 is an equidigital number, since it uses as much as digits as its factorization.

1221211122233 is an evil number, because the sum of its binary digits is even.

The product of its digits is 576, while the sum is 23.

Adding to 1221211122233 its reverse (3322211121221), we get a palindrome (4543422243454).

The spelling of 1221211122233 in words is "one trillion, two hundred twenty-one billion, two hundred eleven million, one hundred twenty-two thousand, two hundred thirty-three".