Base | Representation |
---|---|
bin | 1011000110110101101010… |
… | …1001010110110110111111 |
3 | 1121020110121010202110200012 |
4 | 2301231122221112312333 |
5 | 3100040401340013003 |
6 | 41550100035453435 |
7 | 2400203353123421 |
oct | 261553251266677 |
9 | 47213533673605 |
10 | 12212112813503 |
11 | 3989145350079 |
12 | 1452957a5727b |
13 | 6a779c352415 |
14 | 3030d8686811 |
15 | 1629e999b8d8 |
hex | b1b5aa56dbf |
12212112813503 has 2 divisors, whose sum is σ = 12212112813504. Its totient is φ = 12212112813502.
The previous prime is 12212112813463. The next prime is 12212112813583. The reversal of 12212112813503 is 30531821121221.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12212112813503 - 28 = 12212112813247 is a prime.
It is a Sophie Germain prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12212112813503.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12212112813583) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6106056406751 + 6106056406752.
It is an arithmetic number, because the mean of its divisors is an integer number (6106056406752).
Almost surely, 212212112813503 is an apocalyptic number.
12212112813503 is a deficient number, since it is larger than the sum of its proper divisors (1).
12212112813503 is an equidigital number, since it uses as much as digits as its factorization.
12212112813503 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5760, while the sum is 32.
Adding to 12212112813503 its reverse (30531821121221), we get a palindrome (42743933934724).
The spelling of 12212112813503 in words is "twelve trillion, two hundred twelve billion, one hundred twelve million, eight hundred thirteen thousand, five hundred three".
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