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122121133002000 = 243353112148712569
BaseRepresentation
bin11011110001000110001010…
…110000001000110100010000
3121000101122222201201221222000
4123301012022300020310100
5112001313040022031000
61111421401330314000
734502650343211366
oct3361061260106420
9530348881657860
10122121133002000
1135a03310985300
1211843a88428900
13531ac86812592
1422229a1515636
15e1b9b6cdd000
hex6f118ac08d10

122121133002000 has 960 divisors, whose sum is σ = 481211650483200. Its totient is φ = 29582860032000.

The previous prime is 122121133001983. The next prime is 122121133002007. The reversal of 122121133002000 is 200331121221.

122121133002000 is a `hidden beast` number, since 1 + 221 + 211 + 3 + 30 + 0 + 200 + 0 = 666.

It is a super-2 number, since 2×1221211330020002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is not an unprimeable number, because it can be changed into a prime (122121133002007) by changing a digit.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 9716051716 + ... + 9716064284.

It is an arithmetic number, because the mean of its divisors is an integer number (501262135920).

Almost surely, 2122121133002000 is an apocalyptic number.

122121133002000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 122121133002000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (240605825241600).

122121133002000 is an abundant number, since it is smaller than the sum of its proper divisors (359090517481200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

122121133002000 is a wasteful number, since it uses less digits than its factorization.

122121133002000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14110 (or 14077 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 122121133002000 its reverse (200331121221), we get a palindrome (122321464123221).

The spelling of 122121133002000 in words is "one hundred twenty-two trillion, one hundred twenty-one billion, one hundred thirty-three million, two thousand".