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12212213130031 is a prime number
BaseRepresentation
bin1011000110110110000010…
…1000000010001100101111
31121020110212010112002002011
42301231200220002030233
53100041103030130111
641550114021542051
72400206011604425
oct261554050021457
947213763462064
1012212213130031
113989196a383a2
121452985574927
136a77b7077005
14303107b1b115
15162a036b5021
hexb1b60a0232f

12212213130031 has 2 divisors, whose sum is σ = 12212213130032. Its totient is φ = 12212213130030.

The previous prime is 12212213129999. The next prime is 12212213130133. The reversal of 12212213130031 is 13003131221221.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 12212213130031 - 25 = 12212213129999 is a prime.

It is a super-2 number, since 2×122122131300312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12212213129984 and 12212213130011.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12212213137031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6106106565015 + 6106106565016.

It is an arithmetic number, because the mean of its divisors is an integer number (6106106565016).

Almost surely, 212212213130031 is an apocalyptic number.

12212213130031 is a deficient number, since it is larger than the sum of its proper divisors (1).

12212213130031 is an equidigital number, since it uses as much as digits as its factorization.

12212213130031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 12212213130031 its reverse (13003131221221), we get a palindrome (25215344351252).

The spelling of 12212213130031 in words is "twelve trillion, two hundred twelve billion, two hundred thirteen million, one hundred thirty thousand, thirty-one".