Base | Representation |
---|---|
bin | 111000110111100111… |
… | …1011100100001001011 |
3 | 102200020010111022222211 |
4 | 1301233033130201023 |
5 | 4000103100413420 |
6 | 132034215125551 |
7 | 11552244544132 |
oct | 1615717344113 |
9 | 380203438884 |
10 | 122125404235 |
11 | 4787a67484a |
12 | 1b8036738b7 |
13 | b69362b403 |
14 | 5ca7726919 |
15 | 329b889e5a |
hex | 1c6f3dc84b |
122125404235 has 16 divisors (see below), whose sum is σ = 147328128000. Its totient is φ = 97182419040.
The previous prime is 122125404179. The next prime is 122125404241. The reversal of 122125404235 is 532404521221.
It is a happy number.
It is not a de Polignac number, because 122125404235 - 211 = 122125402187 is a prime.
It is a super-2 number, since 2×1221254042352 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 122125404197 and 122125404206.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1891516 + ... + 1955014.
It is an arithmetic number, because the mean of its divisors is an integer number (9208008000).
Almost surely, 2122125404235 is an apocalyptic number.
122125404235 is a deficient number, since it is larger than the sum of its proper divisors (25202723765).
122125404235 is a wasteful number, since it uses less digits than its factorization.
122125404235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65538.
The product of its (nonzero) digits is 19200, while the sum is 31.
Adding to 122125404235 its reverse (532404521221), we get a palindrome (654529925456).
The spelling of 122125404235 in words is "one hundred twenty-two billion, one hundred twenty-five million, four hundred four thousand, two hundred thirty-five".
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