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1221265325433 = 33331122212081
BaseRepresentation
bin10001110001011001000…
…101011111110101111001
311022202022002011120102010
4101301121011133311321
5130002122410403213
62333012550200133
7154143043662246
oct21613105376571
94282262146363
101221265325433
11430a3248a90a
12178833353049
138b21b1799ca
14431768a65cd
1521b7ba97ac3
hex11c5915fd79

1221265325433 has 8 divisors (see below), whose sum is σ = 1628842628896. Its totient is φ = 813932452800.

The previous prime is 1221265325419. The next prime is 1221265325443. The reversal of 1221265325433 is 3345235621221.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1221265325433 - 29 = 1221265324921 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1221265325391 and 1221265325400.

It is not an unprimeable number, because it can be changed into a prime (1221265325443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 61096048 + ... + 61116033.

It is an arithmetic number, because the mean of its divisors is an integer number (203605328612).

Almost surely, 21221265325433 is an apocalyptic number.

It is an amenable number.

1221265325433 is a deficient number, since it is larger than the sum of its proper divisors (407577303463).

1221265325433 is a wasteful number, since it uses less digits than its factorization.

1221265325433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 122215415.

The product of its digits is 259200, while the sum is 39.

The spelling of 1221265325433 in words is "one trillion, two hundred twenty-one billion, two hundred sixty-five million, three hundred twenty-five thousand, four hundred thirty-three".

Divisors: 1 3 3331 9993 122212081 366636243 407088441811 1221265325433