Base | Representation |
---|---|
bin | 1011000110111000111110… |
… | …1001010101111110011010 |
3 | 1121020112220002220221102201 |
4 | 2301232033221111332122 |
5 | 3100044212003033310 |
6 | 41550324202120414 |
7 | 2400234401113603 |
oct | 261561751257632 |
9 | 47215802827381 |
10 | 12213002002330 |
11 | 3989561268878 |
12 | 1452b657b010a |
13 | 6a78b1631c5c |
14 | 3031807cadaa |
15 | 162a4ca8ee3a |
hex | b1b8fa55f9a |
12213002002330 has 64 divisors (see below), whose sum is σ = 24523451602560. Its totient is φ = 4351964626944.
The previous prime is 12213002002321. The next prime is 12213002002343. The reversal of 12213002002330 is 3320020031221.
It is a Harshad number since it is a multiple of its sum of digits (19).
It is a junction number, because it is equal to n+sod(n) for n = 12213002002298 and 12213002002307.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1943802 + ... + 5310778.
It is an arithmetic number, because the mean of its divisors is an integer number (383178931290).
Almost surely, 212213002002330 is an apocalyptic number.
12213002002330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12213002002330 is an abundant number, since it is smaller than the sum of its proper divisors (12310449600230).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12213002002330 is a wasteful number, since it uses less digits than its factorization.
12213002002330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3368143.
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 12213002002330 its reverse (3320020031221), we get a palindrome (15533022033551).
The spelling of 12213002002330 in words is "twelve trillion, two hundred thirteen billion, two million, two thousand, three hundred thirty".
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