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122130032111027 is a prime number
BaseRepresentation
bin11011110001001110011101…
…001011100010110110110011
3121000102111221220222112120122
4123301032131023202312303
5112001434301210023102
61111425432345200455
734503414022326563
oct3361163513426663
9530374856875518
10122130032111027
1135a07068226666
121184575079012b
13531ba743c9675
1422231a7386da3
15e1bd381db0a2
hex6f139d2e2db3

122130032111027 has 2 divisors, whose sum is σ = 122130032111028. Its totient is φ = 122130032111026.

The previous prime is 122130032110987. The next prime is 122130032111033. The reversal of 122130032111027 is 720111230031221.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 122130032111027 - 210 = 122130032110003 is a prime.

It is a super-3 number, since 3×1221300321110273 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 122130032110987 and 122130032111005.

It is not a weakly prime, because it can be changed into another prime (122130032111047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61065016055513 + 61065016055514.

It is an arithmetic number, because the mean of its divisors is an integer number (61065016055514).

Almost surely, 2122130032111027 is an apocalyptic number.

122130032111027 is a deficient number, since it is larger than the sum of its proper divisors (1).

122130032111027 is an equidigital number, since it uses as much as digits as its factorization.

122130032111027 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1008, while the sum is 26.

Adding to 122130032111027 its reverse (720111230031221), we get a palindrome (842241262142248).

The spelling of 122130032111027 in words is "one hundred twenty-two trillion, one hundred thirty billion, thirty-two million, one hundred eleven thousand, twenty-seven".