Base | Representation |
---|---|
bin | 11011110001001110011101… |
… | …001011100010110110001011 |
3 | 121000102111221220222112112011 |
4 | 123301032131023202312023 |
5 | 112001434301210022422 |
6 | 1111425432345200351 |
7 | 34503414022326505 |
oct | 3361163513426613 |
9 | 530374856875464 |
10 | 122130032110987 |
11 | 35a0706822662a |
12 | 118457507900b7 |
13 | 531ba743c9644 |
14 | 22231a7386d75 |
15 | e1bd381db077 |
hex | 6f139d2e2d8b |
122130032110987 has 2 divisors, whose sum is σ = 122130032110988. Its totient is φ = 122130032110986.
The previous prime is 122130032110973. The next prime is 122130032111027. The reversal of 122130032110987 is 789011230031221.
It is an a-pointer prime, because the next prime (122130032111027) can be obtained adding 122130032110987 to its sum of digits (40).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 122130032110987 - 243 = 113333939088779 is a prime.
It is a super-2 number, since 2×1221300321109872 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (122130032113987) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61065016055493 + 61065016055494.
It is an arithmetic number, because the mean of its divisors is an integer number (61065016055494).
Almost surely, 2122130032110987 is an apocalyptic number.
122130032110987 is a deficient number, since it is larger than the sum of its proper divisors (1).
122130032110987 is an equidigital number, since it uses as much as digits as its factorization.
122130032110987 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36288, while the sum is 40.
The spelling of 122130032110987 in words is "one hundred twenty-two trillion, one hundred thirty billion, thirty-two million, one hundred ten thousand, nine hundred eighty-seven".
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