Base | Representation |
---|---|
bin | 10001110001011011001… |
… | …010111111101101100111 |
3 | 11022202101112000112110221 |
4 | 101301123022333231213 |
5 | 130002210340234002 |
6 | 2333020240225211 |
7 | 154143650305435 |
oct | 21613312775547 |
9 | 4282345015427 |
10 | 1221300321127 |
11 | 430a50212677 |
12 | 17884300b207 |
13 | 8b2254b0813 |
14 | 4317b3b5d55 |
15 | 21b7ebabc37 |
hex | 11c5b2bfb67 |
1221300321127 has 2 divisors, whose sum is σ = 1221300321128. Its totient is φ = 1221300321126.
The previous prime is 1221300321091. The next prime is 1221300321173. The reversal of 1221300321127 is 7211230031221.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1221300321127 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1221300321827) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610650160563 + 610650160564.
It is an arithmetic number, because the mean of its divisors is an integer number (610650160564).
Almost surely, 21221300321127 is an apocalyptic number.
1221300321127 is a deficient number, since it is larger than the sum of its proper divisors (1).
1221300321127 is an equidigital number, since it uses as much as digits as its factorization.
1221300321127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 1221300321127 its reverse (7211230031221), we get a palindrome (8432530352348).
The spelling of 1221300321127 in words is "one trillion, two hundred twenty-one billion, three hundred million, three hundred twenty-one thousand, one hundred twenty-seven".
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