Base | Representation |
---|---|
bin | 10110101111111011… |
… | …01011000010111011 |
3 | 1011112011022000001201 |
4 | 23113331223002323 |
5 | 200003040000011 |
6 | 5335523155031 |
7 | 611440341133 |
oct | 132775530273 |
9 | 34464260051 |
10 | 12213203131 |
11 | 51a8042308 |
12 | 244a215a77 |
13 | 11c839261c |
14 | 83c079ac3 |
15 | 4b7336cc1 |
hex | 2d7f6b0bb |
12213203131 has 2 divisors, whose sum is σ = 12213203132. Its totient is φ = 12213203130.
The previous prime is 12213203129. The next prime is 12213203147. The reversal of 12213203131 is 13130231221.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12213203131 - 21 = 12213203129 is a prime.
It is a super-2 number, since 2×122132031312 (a number of 21 digits) contains 22 as substring.
Together with 12213203129, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 12213203099 and 12213203108.
It is not a weakly prime, because it can be changed into another prime (12213204131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6106601565 + 6106601566.
It is an arithmetic number, because the mean of its divisors is an integer number (6106601566).
Almost surely, 212213203131 is an apocalyptic number.
12213203131 is a deficient number, since it is larger than the sum of its proper divisors (1).
12213203131 is an equidigital number, since it uses as much as digits as its factorization.
12213203131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 12213203131 its reverse (13130231221), we get a palindrome (25343434352).
The spelling of 12213203131 in words is "twelve billion, two hundred thirteen million, two hundred three thousand, one hundred thirty-one".
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