12213211433 has 4 divisors (see below), whose sum is σ = 12215068800. Its totient is φ = 12211354068.

The previous prime is 12213211411. The next prime is 12213211469. The reversal of 12213211433 is 33411231221.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33411231221 = 23 ⋅1452662227.

It is a cyclic number.

It is not a de Polignac number, because 12213211433 - 2¹⁸ = 12212949289 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12213211399 and 12213211408.

It is not an unprimeable number, because it can be changed into a prime (12213211133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 918785 + ... + 931982.

It is an arithmetic number, because the mean of its divisors is an integer number (3053767200).

Almost surely, 2^12213211433 is an apocalyptic number.

It is an amenable number.

12213211433 is a deficient number, since it is larger than the sum of its proper divisors (1857367).

12213211433 is an equidigital number, since it uses as much as digits as its factorization.

12213211433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1857366.

The product of its digits is 864, while the sum is 23.

Adding to 12213211433 its reverse (33411231221), we get a palindrome (45624442654).

The spelling of 12213211433 in words is "twelve billion, two hundred thirteen million, two hundred eleven thousand, four hundred thirty-three".