Base | Representation |
---|---|
bin | 1011000110111010001000… |
… | …0000010001101010111111 |
3 | 1121020120200120111001011101 |
4 | 2301232202000101222333 |
5 | 3100100324330111103 |
6 | 41550414523433531 |
7 | 2400245131100431 |
oct | 261564200215277 |
9 | 47216616431141 |
10 | 12213310003903 |
11 | 39896aa107a28 |
12 | 14530309858a7 |
13 | 6a79303a1ac8 |
14 | 3031ad684651 |
15 | 162a69b2ea1d |
hex | b1ba2011abf |
12213310003903 has 2 divisors, whose sum is σ = 12213310003904. Its totient is φ = 12213310003902.
The previous prime is 12213310003897. The next prime is 12213310003991. The reversal of 12213310003903 is 30930001331221.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12213310003903 - 241 = 10014286748351 is a prime.
It is a super-3 number, since 3×122133100039033 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12213310009903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6106655001951 + 6106655001952.
It is an arithmetic number, because the mean of its divisors is an integer number (6106655001952).
Almost surely, 212213310003903 is an apocalyptic number.
12213310003903 is a deficient number, since it is larger than the sum of its proper divisors (1).
12213310003903 is an equidigital number, since it uses as much as digits as its factorization.
12213310003903 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2916, while the sum is 28.
The spelling of 12213310003903 in words is "twelve trillion, two hundred thirteen billion, three hundred ten million, three thousand, nine hundred three".
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