Base | Representation |
---|---|
bin | 1011000110111010001000… |
… | …0000101100000011111111 |
3 | 1121020120200120200112102221 |
4 | 2301232202000230003333 |
5 | 3100100324342040444 |
6 | 41550414530030211 |
7 | 2400245132030533 |
oct | 261564200540377 |
9 | 47216616615387 |
10 | 12213310111999 |
11 | 39896aa181167 |
12 | 1453030a18367 |
13 | 6a793040c079 |
14 | 3031ad6b1bc3 |
15 | 162a69b51a84 |
hex | b1ba202c0ff |
12213310111999 has 2 divisors, whose sum is σ = 12213310112000. Its totient is φ = 12213310111998.
The previous prime is 12213310111943. The next prime is 12213310112027. The reversal of 12213310111999 is 99911101331221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12213310111999 - 213 = 12213310103807 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12213310141999) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6106655055999 + 6106655056000.
It is an arithmetic number, because the mean of its divisors is an integer number (6106655056000).
Almost surely, 212213310111999 is an apocalyptic number.
12213310111999 is a deficient number, since it is larger than the sum of its proper divisors (1).
12213310111999 is an equidigital number, since it uses as much as digits as its factorization.
12213310111999 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 26244, while the sum is 43.
The spelling of 12213310111999 in words is "twelve trillion, two hundred thirteen billion, three hundred ten million, one hundred eleven thousand, nine hundred ninety-nine".
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