Base | Representation |
---|---|
bin | 111000110111110110… |
… | …0110110001000000011 |
3 | 102200020122222220002122 |
4 | 1301233230312020003 |
5 | 4000112034030144 |
6 | 132035052234455 |
7 | 11552400213533 |
oct | 1615754661003 |
9 | 380218886078 |
10 | 122133111299 |
11 | 47883a59221 |
12 | 1b80616ba2b |
13 | b6950c93c4 |
14 | 5ca87714c3 |
15 | 329c3ad7ee |
hex | 1c6fb36203 |
122133111299 has 2 divisors, whose sum is σ = 122133111300. Its totient is φ = 122133111298.
The previous prime is 122133111283. The next prime is 122133111301. The reversal of 122133111299 is 992111331221.
It is a strong prime.
It is an emirp because it is prime and its reverse (992111331221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 122133111299 - 24 = 122133111283 is a prime.
Together with 122133111301, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (122133111799) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61066555649 + 61066555650.
It is an arithmetic number, because the mean of its divisors is an integer number (61066555650).
Almost surely, 2122133111299 is an apocalyptic number.
122133111299 is a deficient number, since it is larger than the sum of its proper divisors (1).
122133111299 is an equidigital number, since it uses as much as digits as its factorization.
122133111299 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 5832, while the sum is 35.
The spelling of 122133111299 in words is "one hundred twenty-two billion, one hundred thirty-three million, one hundred eleven thousand, two hundred ninety-nine".
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