Base | Representation |
---|---|
bin | 10001110001011101000… |
… | …000110101000001000111 |
3 | 11022202110200010212110210 |
4 | 101301131000311001013 |
5 | 130002241242212221 |
6 | 2333023302250503 |
7 | 154144503666402 |
oct | 21613500650107 |
9 | 4282420125423 |
10 | 1221331210311 |
11 | 430a666a0123 |
12 | 178851426a33 |
13 | 8b22ba07444 |
14 | 43181536d39 |
15 | 21b8275e276 |
hex | 11c5d035047 |
1221331210311 has 16 divisors (see below), whose sum is σ = 1644497008128. Its totient is φ = 806227788000.
The previous prime is 1221331210303. The next prime is 1221331210327. The reversal of 1221331210311 is 1130121331221.
It is not a de Polignac number, because 1221331210311 - 23 = 1221331210303 is a prime.
It is a super-2 number, since 2×12213312103112 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1221331210391) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4193676 + ... + 4475441.
It is an arithmetic number, because the mean of its divisors is an integer number (102781063008).
Almost surely, 21221331210311 is an apocalyptic number.
1221331210311 is a deficient number, since it is larger than the sum of its proper divisors (423165797817).
1221331210311 is a wasteful number, since it uses less digits than its factorization.
1221331210311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8669582.
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 1221331210311 its reverse (1130121331221), we get a palindrome (2351452541532).
The spelling of 1221331210311 in words is "one trillion, two hundred twenty-one billion, three hundred thirty-one million, two hundred ten thousand, three hundred eleven".
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