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122133130130993 is a prime number
BaseRepresentation
bin11011110001010001010101…
…110101100011011000110001
3121000102210221211110021000212
4123301101111311203120301
5112002012122303142433
61111431104014353505
734503553551140012
oct3361212565433061
9530383854407025
10122133130130993
1135a08407a55943
12118462761bb895
13531c1491b0387
1422233bc9c7009
15e1be6a192d48
hex6f1455d63631

122133130130993 has 2 divisors, whose sum is σ = 122133130130994. Its totient is φ = 122133130130992.

The previous prime is 122133130130959. The next prime is 122133130131043. The reversal of 122133130130993 is 399031031331221.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 114690884240689 + 7442245890304 = 10709383^2 + 2728048^2 .

It is a cyclic number.

It is not a de Polignac number, because 122133130130993 - 26 = 122133130130929 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 122133130130993.

It is not a weakly prime, because it can be changed into another prime (122133130136993) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61066565065496 + 61066565065497.

It is an arithmetic number, because the mean of its divisors is an integer number (61066565065497).

Almost surely, 2122133130130993 is an apocalyptic number.

It is an amenable number.

122133130130993 is a deficient number, since it is larger than the sum of its proper divisors (1).

122133130130993 is an equidigital number, since it uses as much as digits as its factorization.

122133130130993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 78732, while the sum is 41.

The spelling of 122133130130993 in words is "one hundred twenty-two trillion, one hundred thirty-three billion, one hundred thirty million, one hundred thirty thousand, nine hundred ninety-three".