Base | Representation |
---|---|
bin | 1011000110111010001001… |
… | …0001001010101001000011 |
3 | 1121020120200212210222202111 |
4 | 2301232202101022221003 |
5 | 3100100331443302210 |
6 | 41550415202400151 |
7 | 2400245213531146 |
oct | 261564221125103 |
9 | 47216625728674 |
10 | 12213314431555 |
11 | 3989701661546 |
12 | 1453032360057 |
13 | 6a7931292213 |
14 | 3031b00b805d |
15 | 162a6a20688a |
hex | b1ba244aa43 |
12213314431555 has 16 divisors (see below), whose sum is σ = 14936521590720. Its totient is φ = 9583721200768.
The previous prime is 12213314431511. The next prime is 12213314431573. The reversal of 12213314431555 is 55513441331221.
It is a cyclic number.
It is not a de Polignac number, because 12213314431555 - 27 = 12213314431427 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5210752 + ... + 7181821.
It is an arithmetic number, because the mean of its divisors is an integer number (933532599420).
Almost surely, 212213314431555 is an apocalyptic number.
12213314431555 is a deficient number, since it is larger than the sum of its proper divisors (2723207159165).
12213314431555 is a wasteful number, since it uses less digits than its factorization.
12213314431555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12396350.
The product of its digits is 216000, while the sum is 40.
Adding to 12213314431555 its reverse (55513441331221), we get a palindrome (67726755762776).
The spelling of 12213314431555 in words is "twelve trillion, two hundred thirteen billion, three hundred fourteen million, four hundred thirty-one thousand, five hundred fifty-five".
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