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12213314431555 = 553371912392573
BaseRepresentation
bin1011000110111010001001…
…0001001010101001000011
31121020120200212210222202111
42301232202101022221003
53100100331443302210
641550415202400151
72400245213531146
oct261564221125103
947216625728674
1012213314431555
113989701661546
121453032360057
136a7931292213
143031b00b805d
15162a6a20688a
hexb1ba244aa43

12213314431555 has 16 divisors (see below), whose sum is σ = 14936521590720. Its totient is φ = 9583721200768.

The previous prime is 12213314431511. The next prime is 12213314431573. The reversal of 12213314431555 is 55513441331221.

It is a cyclic number.

It is not a de Polignac number, because 12213314431555 - 27 = 12213314431427 is a prime.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5210752 + ... + 7181821.

It is an arithmetic number, because the mean of its divisors is an integer number (933532599420).

Almost surely, 212213314431555 is an apocalyptic number.

12213314431555 is a deficient number, since it is larger than the sum of its proper divisors (2723207159165).

12213314431555 is a wasteful number, since it uses less digits than its factorization.

12213314431555 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12396350.

The product of its digits is 216000, while the sum is 40.

Adding to 12213314431555 its reverse (55513441331221), we get a palindrome (67726755762776).

The spelling of 12213314431555 in words is "twelve trillion, two hundred thirteen billion, three hundred fourteen million, four hundred thirty-one thousand, five hundred fifty-five".

Divisors: 1 5 53 265 3719 18595 197107 985535 12392573 61962865 656806369 3284031845 46087978987 230439894935 2442662886311 12213314431555