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12213343155197 is a prime number
BaseRepresentation
bin1011000110111010001111…
…1110101111001111111101
31121020120202212212022012002
42301232203332233033331
53100100411321431242
641550422110152045
72400246012632432
oct261564376571775
947216685768162
1012213343155197
11398971689aa98
12145303bab2625
136a793720b262
143031b3c33b89
15162a6c9cc432
hexb1ba3faf3fd

12213343155197 has 2 divisors, whose sum is σ = 12213343155198. Its totient is φ = 12213343155196.

The previous prime is 12213343155173. The next prime is 12213343155241. The reversal of 12213343155197 is 79155134331221.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12058909088836 + 154434066361 = 3472594^2 + 392981^2 .

It is a cyclic number.

It is not a de Polignac number, because 12213343155197 - 26 = 12213343155133 is a prime.

It is a super-2 number, since 2×122133431551972 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12213343155127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6106671577598 + 6106671577599.

It is an arithmetic number, because the mean of its divisors is an integer number (6106671577599).

Almost surely, 212213343155197 is an apocalyptic number.

It is an amenable number.

12213343155197 is a deficient number, since it is larger than the sum of its proper divisors (1).

12213343155197 is an equidigital number, since it uses as much as digits as its factorization.

12213343155197 is an evil number, because the sum of its binary digits is even.

The product of its digits is 680400, while the sum is 47.

The spelling of 12213343155197 in words is "twelve trillion, two hundred thirteen billion, three hundred forty-three million, one hundred fifty-five thousand, one hundred ninety-seven".