Base | Representation |
---|---|
bin | 111000110111111000… |
… | …0110111011111011111 |
3 | 102200020201222110011001 |
4 | 1301233300313133133 |
5 | 4000112321243341 |
6 | 132035131011131 |
7 | 11552412164113 |
oct | 1615760673737 |
9 | 380221873131 |
10 | 122134165471 |
11 | 4788460923a |
12 | 1b806599aa7 |
13 | b6953a8186 |
14 | 5ca8967743 |
15 | 329c51ad31 |
hex | 1c6fc377df |
122134165471 has 2 divisors, whose sum is σ = 122134165472. Its totient is φ = 122134165470.
The previous prime is 122134165399. The next prime is 122134165477. The reversal of 122134165471 is 174561431221.
It is a strong prime.
It is an emirp because it is prime and its reverse (174561431221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 122134165471 - 27 = 122134165343 is a prime.
It is a super-3 number, since 3×1221341654713 (a number of 34 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 122134165471.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (122134165477) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61067082735 + 61067082736.
It is an arithmetic number, because the mean of its divisors is an integer number (61067082736).
Almost surely, 2122134165471 is an apocalyptic number.
122134165471 is a deficient number, since it is larger than the sum of its proper divisors (1).
122134165471 is an equidigital number, since it uses as much as digits as its factorization.
122134165471 is an evil number, because the sum of its binary digits is even.
The product of its digits is 40320, while the sum is 37.
Adding to 122134165471 its reverse (174561431221), we get a palindrome (296695596692).
The spelling of 122134165471 in words is "one hundred twenty-two billion, one hundred thirty-four million, one hundred sixty-five thousand, four hundred seventy-one".
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