Base | Representation |
---|---|
bin | 10001110001100001001… |
… | …000000000101111011011 |
3 | 11022202122110222000120001 |
4 | 101301201020000233123 |
5 | 130002411422432303 |
6 | 2333034205113431 |
7 | 154146302264056 |
oct | 21614110005733 |
9 | 4282573860501 |
10 | 1221400202203 |
11 | 430aa1632815 |
12 | 178870558877 |
13 | 8b2400b214c |
14 | 4318a775a9d |
15 | 21b8883b31d |
hex | 11c61200bdb |
1221400202203 has 2 divisors, whose sum is σ = 1221400202204. Its totient is φ = 1221400202202.
The previous prime is 1221400202171. The next prime is 1221400202207. The reversal of 1221400202203 is 3022020041221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1221400202203 - 25 = 1221400202171 is a prime.
It is not a weakly prime, because it can be changed into another prime (1221400202207) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610700101101 + 610700101102.
It is an arithmetic number, because the mean of its divisors is an integer number (610700101102).
Almost surely, 21221400202203 is an apocalyptic number.
1221400202203 is a deficient number, since it is larger than the sum of its proper divisors (1).
1221400202203 is an equidigital number, since it uses as much as digits as its factorization.
1221400202203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 384, while the sum is 19.
Adding to 1221400202203 its reverse (3022020041221), we get a palindrome (4243420243424).
The spelling of 1221400202203 in words is "one trillion, two hundred twenty-one billion, four hundred million, two hundred two thousand, two hundred three".
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