Base | Representation |
---|---|
bin | 10001110001100001111… |
… | …001010011110100101001 |
3 | 11022202200101021120212121 |
4 | 101301201321103310221 |
5 | 130002423230003132 |
6 | 2333035350111241 |
7 | 154146520160062 |
oct | 21614171236451 |
9 | 4282611246777 |
10 | 1221413125417 |
11 | 430aa895a161 |
12 | 17887494b521 |
13 | 8b242988414 |
14 | 4318c37b569 |
15 | 21b89a40497 |
hex | 11c61e53d29 |
1221413125417 has 2 divisors, whose sum is σ = 1221413125418. Its totient is φ = 1221413125416.
The previous prime is 1221413125411. The next prime is 1221413125433. The reversal of 1221413125417 is 7145213141221.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1068847890201 + 152565235216 = 1033851^2 + 390596^2 .
It is a cyclic number.
It is not a de Polignac number, because 1221413125417 - 23 = 1221413125409 is a prime.
It is not a weakly prime, because it can be changed into another prime (1221413125411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610706562708 + 610706562709.
It is an arithmetic number, because the mean of its divisors is an integer number (610706562709).
Almost surely, 21221413125417 is an apocalyptic number.
It is an amenable number.
1221413125417 is a deficient number, since it is larger than the sum of its proper divisors (1).
1221413125417 is an equidigital number, since it uses as much as digits as its factorization.
1221413125417 is an evil number, because the sum of its binary digits is even.
The product of its digits is 13440, while the sum is 34.
Adding to 1221413125417 its reverse (7145213141221), we get a palindrome (8366626266638).
The spelling of 1221413125417 in words is "one trillion, two hundred twenty-one billion, four hundred thirteen million, one hundred twenty-five thousand, four hundred seventeen".
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