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1221413125433 is a prime number
BaseRepresentation
bin10001110001100001111…
…001010011110100111001
311022202200101021120220012
4101301201321103310321
5130002423230003213
62333035350111305
7154146520160114
oct21614171236471
94282611246805
101221413125433
11430aa895a176
1217887494b535
138b242988427
144318c37b57b
1521b89a404a8
hex11c61e53d39

1221413125433 has 2 divisors, whose sum is σ = 1221413125434. Its totient is φ = 1221413125432.

The previous prime is 1221413125417. The next prime is 1221413125447. The reversal of 1221413125433 is 3345213141221.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1218568716544 + 2844408889 = 1103888^2 + 53333^2 .

It is a cyclic number.

It is not a de Polignac number, because 1221413125433 - 24 = 1221413125417 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1221413125433.

It is not a weakly prime, because it can be changed into another prime (1221413125133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610706562716 + 610706562717.

It is an arithmetic number, because the mean of its divisors is an integer number (610706562717).

Almost surely, 21221413125433 is an apocalyptic number.

It is an amenable number.

1221413125433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1221413125433 is an equidigital number, since it uses as much as digits as its factorization.

1221413125433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 17280, while the sum is 32.

Adding to 1221413125433 its reverse (3345213141221), we get a palindrome (4566626266654).

The spelling of 1221413125433 in words is "one trillion, two hundred twenty-one billion, four hundred thirteen million, one hundred twenty-five thousand, four hundred thirty-three".