Base | Representation |
---|---|
bin | 10001110001100001111… |
… | …001010011110100111001 |
3 | 11022202200101021120220012 |
4 | 101301201321103310321 |
5 | 130002423230003213 |
6 | 2333035350111305 |
7 | 154146520160114 |
oct | 21614171236471 |
9 | 4282611246805 |
10 | 1221413125433 |
11 | 430aa895a176 |
12 | 17887494b535 |
13 | 8b242988427 |
14 | 4318c37b57b |
15 | 21b89a404a8 |
hex | 11c61e53d39 |
1221413125433 has 2 divisors, whose sum is σ = 1221413125434. Its totient is φ = 1221413125432.
The previous prime is 1221413125417. The next prime is 1221413125447. The reversal of 1221413125433 is 3345213141221.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1218568716544 + 2844408889 = 1103888^2 + 53333^2 .
It is a cyclic number.
It is not a de Polignac number, because 1221413125433 - 24 = 1221413125417 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1221413125433.
It is not a weakly prime, because it can be changed into another prime (1221413125133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610706562716 + 610706562717.
It is an arithmetic number, because the mean of its divisors is an integer number (610706562717).
Almost surely, 21221413125433 is an apocalyptic number.
It is an amenable number.
1221413125433 is a deficient number, since it is larger than the sum of its proper divisors (1).
1221413125433 is an equidigital number, since it uses as much as digits as its factorization.
1221413125433 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 17280, while the sum is 32.
Adding to 1221413125433 its reverse (3345213141221), we get a palindrome (4566626266654).
The spelling of 1221413125433 in words is "one trillion, two hundred twenty-one billion, four hundred thirteen million, one hundred twenty-five thousand, four hundred thirty-three".
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