Base | Representation |
---|---|
bin | 11011110001011010111010… |
… | …110000110001011000011011 |
3 | 121000110210111111001221002202 |
4 | 123301122322300301120123 |
5 | 112002144202301423003 |
6 | 1111435524234520415 |
7 | 34504366434545450 |
oct | 3361327260613033 |
9 | 530423444057082 |
10 | 122143413311003 |
11 | 35a118045a6217 |
12 | 11848265b9610b |
13 | 53200c7759786 |
14 | 2223ab65c1827 |
15 | e1c36cd3b088 |
hex | 6f16bac3161b |
122143413311003 has 8 divisors (see below), whose sum is σ = 139634179126272. Its totient is φ = 104663074188456.
The previous prime is 122143413310969. The next prime is 122143413311011. The reversal of 122143413311003 is 300113314341221.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 122143413311003 - 210 = 122143413309979 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (122143413361003) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2606648075 + ... + 2606694932.
It is an arithmetic number, because the mean of its divisors is an integer number (17454272390784).
Almost surely, 2122143413311003 is an apocalyptic number.
122143413311003 is a deficient number, since it is larger than the sum of its proper divisors (17490765815269).
122143413311003 is an equidigital number, since it uses as much as digits as its factorization.
122143413311003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5213346361.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 122143413311003 its reverse (300113314341221), we get a palindrome (422256727652224).
The spelling of 122143413311003 in words is "one hundred twenty-two trillion, one hundred forty-three billion, four hundred thirteen million, three hundred eleven thousand, three".
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