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1221444244313 is a prime number
BaseRepresentation
bin10001110001100011110…
…000000001001101011001
311022202202112211120222022
4101301203300001031121
5130003004211304223
62333042421104225
7154150345525526
oct21614360011531
94282675746868
101221444244313
11431014484257
12178883258075
138b249262777
144319255c14d
1521b8c63aac8
hex11c63c01359

1221444244313 has 2 divisors, whose sum is σ = 1221444244314. Its totient is φ = 1221444244312.

The previous prime is 1221444244309. The next prime is 1221444244373. The reversal of 1221444244313 is 3134424441221.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 887207634889 + 334236609424 = 941917^2 + 578132^2 .

It is an emirp because it is prime and its reverse (3134424441221) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1221444244313 - 22 = 1221444244309 is a prime.

It is not a weakly prime, because it can be changed into another prime (1221444244373) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610722122156 + 610722122157.

It is an arithmetic number, because the mean of its divisors is an integer number (610722122157).

Almost surely, 21221444244313 is an apocalyptic number.

It is an amenable number.

1221444244313 is a deficient number, since it is larger than the sum of its proper divisors (1).

1221444244313 is an equidigital number, since it uses as much as digits as its factorization.

1221444244313 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 73728, while the sum is 35.

Adding to 1221444244313 its reverse (3134424441221), we get a palindrome (4355868685534).

The spelling of 1221444244313 in words is "one trillion, two hundred twenty-one billion, four hundred forty-four million, two hundred forty-four thousand, three hundred thirteen".